Day 9 Electric Fields

Electric fields are electric force per charge. We typically use positive test point charge thus electric fields radiate outward.

We were asked to explain gravitational force of attraction and compare to electrical fields. As a group it was hard to explain. The field of G and the field of E are similar. We came up with the conclusion that electric fields are caused by charges, the magnitude of the electric field depends on the magnitude of the charge and magnitude of the electric fields depends on distance as well, lastly mass creates charge.

We then had Active Physics lab questions. We had to use E = F/q for each point and each electric field.
White board work is missing. :( But conclusion was the negative number means is inward field and positive number means outward field.

Prof. Mason then demonstrated with charges and electrical fields with how a marvel moves around. We came with the conlusion that the marvel moves in circular paths in and out of the center. Anwser to number 5 is the same or uniform becuase the eletric field is uniform. And anwser 6 is that force changes direction towards +q.Again, the video and pictures of the demonstration is missing. :(

We then did the Active Physics lab.

The final result was that the F = <18.1 N/C, 12.8N/C>

We then did the example of a uniform bar charged at a distance away.

Did some white board work. The answer for E was cut out but was found to be 52,600 N/C.

We then used a spread sheet to find the vertical  component of charge.

Visual diagram of what was happening.

The charge was found to be 1.27*10^5 N/C from the spread sheet.

Picture of spread sheet.

We then had to do some calculus to find an expression for Electric fields.

Found the expression for E. We can plug and chug from this point. And it turns out to be 5.9*10^4 C.

Summary:
Defined what Electrical Fields were and how they relate to Gravity Fields.
Found how E = F/q. If E is negative the field is inward, if E is positive the field is outward.
Did some Active Physics problems to find E and Forces. Used a spread sheet to find q vertical of a uniformed charge rod.
Dervived an expression for E to be used. KQ/d(d+L).